Optimal. Leaf size=286 \[ -\frac {3 b^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 a^{7/4} \sqrt {a x+b x^3}}+\frac {6 b^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 a^{7/4} \sqrt {a x+b x^3}}-\frac {6 b^{3/2} x \left (a+b x^2\right )}{5 a^2 \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}}+\frac {6 b \sqrt {a x+b x^3}}{5 a^2 x}-\frac {2 \sqrt {a x+b x^3}}{5 a x^3} \]
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Rubi [A] time = 0.25, antiderivative size = 286, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.353, Rules used = {2025, 2032, 329, 305, 220, 1196} \[ -\frac {6 b^{3/2} x \left (a+b x^2\right )}{5 a^2 \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}}-\frac {3 b^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 a^{7/4} \sqrt {a x+b x^3}}+\frac {6 b^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 a^{7/4} \sqrt {a x+b x^3}}+\frac {6 b \sqrt {a x+b x^3}}{5 a^2 x}-\frac {2 \sqrt {a x+b x^3}}{5 a x^3} \]
Antiderivative was successfully verified.
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Rule 220
Rule 305
Rule 329
Rule 1196
Rule 2025
Rule 2032
Rubi steps
\begin {align*} \int \frac {1}{x^3 \sqrt {a x+b x^3}} \, dx &=-\frac {2 \sqrt {a x+b x^3}}{5 a x^3}-\frac {(3 b) \int \frac {1}{x \sqrt {a x+b x^3}} \, dx}{5 a}\\ &=-\frac {2 \sqrt {a x+b x^3}}{5 a x^3}+\frac {6 b \sqrt {a x+b x^3}}{5 a^2 x}-\frac {\left (3 b^2\right ) \int \frac {x}{\sqrt {a x+b x^3}} \, dx}{5 a^2}\\ &=-\frac {2 \sqrt {a x+b x^3}}{5 a x^3}+\frac {6 b \sqrt {a x+b x^3}}{5 a^2 x}-\frac {\left (3 b^2 \sqrt {x} \sqrt {a+b x^2}\right ) \int \frac {\sqrt {x}}{\sqrt {a+b x^2}} \, dx}{5 a^2 \sqrt {a x+b x^3}}\\ &=-\frac {2 \sqrt {a x+b x^3}}{5 a x^3}+\frac {6 b \sqrt {a x+b x^3}}{5 a^2 x}-\frac {\left (6 b^2 \sqrt {x} \sqrt {a+b x^2}\right ) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 a^2 \sqrt {a x+b x^3}}\\ &=-\frac {2 \sqrt {a x+b x^3}}{5 a x^3}+\frac {6 b \sqrt {a x+b x^3}}{5 a^2 x}-\frac {\left (6 b^{3/2} \sqrt {x} \sqrt {a+b x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 a^{3/2} \sqrt {a x+b x^3}}+\frac {\left (6 b^{3/2} \sqrt {x} \sqrt {a+b x^2}\right ) \operatorname {Subst}\left (\int \frac {1-\frac {\sqrt {b} x^2}{\sqrt {a}}}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 a^{3/2} \sqrt {a x+b x^3}}\\ &=-\frac {6 b^{3/2} x \left (a+b x^2\right )}{5 a^2 \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}}-\frac {2 \sqrt {a x+b x^3}}{5 a x^3}+\frac {6 b \sqrt {a x+b x^3}}{5 a^2 x}+\frac {6 b^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 a^{7/4} \sqrt {a x+b x^3}}-\frac {3 b^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 a^{7/4} \sqrt {a x+b x^3}}\\ \end {align*}
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Mathematica [C] time = 0.01, size = 53, normalized size = 0.19 \[ -\frac {2 \sqrt {\frac {b x^2}{a}+1} \, _2F_1\left (-\frac {5}{4},\frac {1}{2};-\frac {1}{4};-\frac {b x^2}{a}\right )}{5 x^2 \sqrt {x \left (a+b x^2\right )}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.60, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {b x^{3} + a x}}{b x^{6} + a x^{4}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {b x^{3} + a x} x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.07, size = 204, normalized size = 0.71 \[ \frac {6 \left (b \,x^{2}+a \right ) b}{5 \sqrt {\left (b \,x^{2}+a \right ) x}\, a^{2}}-\frac {3 \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {b x}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, \EllipticE \left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}+\frac {\sqrt {-a b}\, \EllipticF \left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}\right ) b}{5 \sqrt {b \,x^{3}+a x}\, a^{2}}-\frac {2 \sqrt {b \,x^{3}+a x}}{5 a \,x^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {b x^{3} + a x} x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {1}{x^3\,\sqrt {b\,x^3+a\,x}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{3} \sqrt {x \left (a + b x^{2}\right )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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